Copy based on condition in target cell
Sub waniek()
Dim MyLastRow As Long
Dim MyRange As Range
Dim StartRow As Long
Dim MyRow As Long
Dim rDest As Range
Dim i As Long
MyLastRow = Cells(40000, 7).End(xlUp).Row
Set MyRange = Range("a1:k" & MyLastRow)
i = 1
Do While i < MyLastRow
If Range("g" & i) = "" Then
Set rDest = Range("g" & i)
MyRow = i
Range("f" & MyRow).Copy Destination:=rDest
rDest.Font.ColorIndex = 5
End If
i = i + 1
Loop
End Sub
On Jan 31, 6:11 pm, JWaniek wrote:
I am not a VBA or Excel macro specialist, which is why I cannot come up
with a solution to this problem on my own.
I have a spreadsheet with several thousand rows. Column G has a bunch of
empty cells. I want to go down row by row and copy the contents of the cell
in column F into the cell next to it in column G if the cell in column G is
empty and then change the text color of the cell in column G to blue.
Something like:
If Gx is empty
copy Fx to Gx
color Gx blue
The above is easy to record in a macro for one cell, but how do I write a
macro that goes down all 3,000 rows and executes this?
Any help would be greatly appreciated.
Jesko Waniek
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