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If Active Sheet on Opening is X then do Y
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spences10
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If Active Sheet on Opening is X then do Y
Hi Galimi,
as instructed i entered the debug and the [same as before] following
error appeared : Run-Time Error '451'
Property let procedurenot defined and property get procedure did not
return an object
I'm totally lost....
Scott
galimi wrote:
It may be showing the workbook name as Option1.xls. To verify, put a
debug.print activesheet.name statement in at the very top of your module.
--
http://HelpExcel.com
"spences10" wrote:
Hi, I'm having trouble with the below code. I want the open procedure
to exit the code if the active sheet on opening is "Option1" can
anyone help please??
Private Sub Workbook_Open()
Application.ScreenUpdating = False
If ActiveSheet.Name("Option1") Then
Exit Sub
End If
ActiveWorkbook.Sheets("Input").Activate
If Range("D30") < "" Then
ActiveWorkbook.Sheets("Default").Select
Exit Sub
End If
UserForm2.Show
Application.ScreenUpdating = True
End Sub
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