If you wanted slightly shorter, and the range is from J, then you could use
=CHAR(73+MATCH(MAX(J8:T8),J8:T8,0))
--
Regards
Ken....................... Microsoft MVP - Excel
Sys Spec - Win XP Pro / XL 97/00/02/03
------------------------------*------------------------------*----------------
It's easier to beg forgiveness than ask permission :-)
------------------------------*------------------------------*----------------
"Michael Link" wrote in message
...
Thanks, Ken! Actually, this will work fine--my range will never go past
"z,"
so your idea works just spiffily! Excellent!
M. Link
Grateful functionary
"Ken Wright" wrote:
=LEFT(Your_Formula)
Not really flexible though as will fall over if you went past Z in your
ranges, but works for your example. Do you need to go past Z?
--
Regards
Ken....................... Microsoft MVP - Excel
Sys Spec - Win XP Pro / XL 97/00/02/03
------------------------------*------------------------------*----------------
It's easier to beg forgiveness than ask permission :-)
------------------------------*------------------------------*----------------
"Michael Link" wrote in message
...
Hi--
I have a range of cells J8:T8. The following formula returns the
address
of
the cell with the highest value in that range:
=ADDRESS(8,9+MATCH(MAX(J8:T8),J8:T8,0),4)
Does anyone know how I might modify this so that it returns only the
column
number in the address? If, for example, the highest value is in cell
R8, I
need the formula to return only "R".
I know this sounds stupid, but if anyone can assist, I'd be very
appreciative!
Michael Link
Hapless low-level corporate functionary
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