Reading Norman's answer, I realise I read it back to front. But if you want
to generate more than 4 numbers, more than 256, you have a problem as you
only have 256 columns. Is that an issue?

--
HTH

Bob Phillips

(replace somewhere in email address with gmail if mailing direct)

"Bob Phillips" wrote in message
...
Sub GetThem()
Dim j As Long
Dim N As Long
Const LNG_PLUG As Long = 999
Const NUM_GENERATED As Long = 799 '<=== change to suit
Dim arrCheck(1 To NUM_GENERATED + 1) As Long
Dim arrList(1 To NUM_GENERATED) As Long

j = 1
Do While j < NUM_GENERATED
'Get a random number
Randomize
N = Int(Rnd * NUM_GENERATED + 1)
'If number unique then add to arrList.
If arrCheck(N) < LNG_PLUG Then
arrList(j) = N
arrCheck(N) = LNG_PLUG
j = j + 1
End If
Loop
Sheets(1).Range("A1:A" & NUM_GENERATED).Value =
Application.Transpose(arrList())
End Sub


--
HTH

Bob Phillips

(replace somewhere in email address with gmail if mailing direct)

"Ozgur Pars" wrote in message
...
Hi everyone,
I found the below code on this board (I think it originated from Tom
Ogilvy). I need to put the generated numbers in a row but the list
generated
is designed for a column (if this makes any sense at all).
Its probably simple but I am new at this stuff and would appreciate any
help.

Rgds,
Ozgur

Sub GetThem()
Dim arrCheck(1 To 800) As Long
Dim arrList(1 To 799) As Long
Dim j As Long
Dim N As Long
Const LNG_PLUG As Long = 999

j = 1
Do While j < 4
'Get a random number
Randomize
N = Int(Rnd * 800 + 1)
'If number unique then add to arrList.
If arrCheck(N) < LNG_PLUG Then
arrList(j) = N
arrCheck(N) = LNG_PLUG
j = j + 1
End If
Loop
Sheets(1).Range("A4:A6").Value = arrList()
' Sheets(1).Range(Cells(5, 1), Cells(5, Sheets(1).Range("b1"))).Value =
arrList()
End Sub