function showing false result when it is not
On Jan 30, 8:11*pm, "Cimjet" wrote:
Hi Amy-Marie
What you have is an array formula.
You enter an array formula by pressing ctrl+shift+Enter instead of
just Enter. *If you do it right; Excel will display an array formula surrounded
by curly braces in the Formula Bar. *You cannot type the curly braces yourself.
* If you make a mistake, select the cell, double click on it to go to Edit mode
or press F2 and edit as needed, then press ctrl+shift+Enter.
But I'm not sure that's what you want.
Your formula will count all the "1" if there is 1 "P".
If it's not what you want, explain it in detail."Amy-Marie" wrote in message
...
On Jan 30, 7:49 pm, GS wrote:
Amy-Marie pretended :
Can anyone see what is wrong with this function? =IF('Employee
Details'!V4:V93="P",COUNTIF('Employee Details'!Y4:Y93,1),0) - There
are loads of "P"'s in that range but it is still showing 0 as if it is
false. How this makes sense. Its driving me mad!!!
How do you know the zero is not the result of there being none of your
COUNTIF criteria?
--
Garry
Free usenet access athttp://www.eternal-september.org
ClassicVB Users Regroup! comp.lang.basic.visual.misc
There are loads of 1's, it is just not counting them. The elements of
the formula are for the right ranges as well.
Cimjet,
I tried ctrl,shift and enter and the curly braces appeared and it then
counted ALL of the 1's rather than just the 1's that have a "P" in the
cell next to it. All I want is the formula to count all the 1's that
have a P in the cell next to it only. Does that make sense?
Many thanks
Amy
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