function showing false result when it is not
Hi Amy-Marie
What you have is an array formula.
You enter an array formula by pressing ctrl+shift+Enter instead of
just Enter. If you do it right; Excel will display an array formula surrounded
by curly braces in the Formula Bar. You cannot type the curly braces yourself.
If you make a mistake, select the cell, double click on it to go to Edit mode
or press F2 and edit as needed, then press ctrl+shift+Enter.
But I'm not sure that's what you want.
Your formula will count all the "1" if there is 1 "P".
If it's not what you want, explain it in detail.
"Amy-Marie" wrote in message
...
On Jan 30, 7:49 pm, GS wrote:
Amy-Marie pretended :
Can anyone see what is wrong with this function? =IF('Employee
Details'!V4:V93="P",COUNTIF('Employee Details'!Y4:Y93,1),0) - There
are loads of "P"'s in that range but it is still showing 0 as if it is
false. How this makes sense. Its driving me mad!!!
How do you know the zero is not the result of there being none of your
COUNTIF criteria?
--
Garry
Free usenet access athttp://www.eternal-september.org
ClassicVB Users Regroup! comp.lang.basic.visual.misc
There are loads of 1's, it is just not counting them. The elements of
the formula are for the right ranges as well.
|