Well, you could tell us what version of XL your are using.
You could also tell us how/if the proposed solutions to
your original question worked.
--
Jim Cone
San Francisco, USA
http://www.realezsites.com/bus/primitivesoftware



"crazy_vba"
wrote in message

Jim Cone Wrote:
Note that your method to find the numerics in the string will
fail when the number of characters in the string changes.


You're exactly right. It didn't work few minutes ago...If i want it to
work, I have to change the value indicating the n° of characters...
damn.
what can I do ? _<