XL2003 open .CSV problem
Stefi,
Excel takes the delimiter from the Windows setting Regional
OptionsNumbersList Separator.
Set that to a semi colon or use the DataGet external dataImport Text file
menu.
NickHK
"Stefi" wrote in message
...
Hi All,
Earlier I used XL2000, and I had a macro opening a .CSV file:
Workbooks.Open Filename:="C:\Myfolder\2005_12.csv"
worked correctly, it placed the semicolon-separated data into different
columns (I use a Hungarian version where list separator is semicolon).
Recently I had to upgrade to XL2003 (because I couldn't go without some
feature existing only in XL2003), and this statement doesn't work
correctly
in XL2003: it opens the .csv file, but does NOT place the
semicolon-separated
data into different columns.
I tried
Workbooks.Open Filename:="C:\Myfolder\2005_12.csv", Format:=4
Workbooks.Open Filename:="C:\Myfolder\2005_12.csv", Format:=6,
delimiter:=";"
with the same result.
Can anybody help?
Regards,
Stefi
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