Snippet from VBA Help:

fileToOpen = Application _
.GetOpenFilename("Text Files (*.txt), *.txt")
If fileToOpen < False Then
MsgBox "Open " & fileToOpen
End IfHTH--AP"sam" a écrit dans le message de
oups.com...
Hi Tim,

But in this function i cannot give the input?

Please show me the code

Thank you,
Sunil