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Niek Otten Niek Otten is offline
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Default implement test="=(SUM(R[-181]C:R[-170]C)-string1)/string2 "inV

If there are decimal separators in Depreciation, they should be the International ones, not your local ones.
Or use the FormulaR1C1Local property instead.

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Kind regards,

Niek Otten


"Monika" wrote in message ...

This works:
teststreng = "=SUM(R[" & s - 183 & "]C:R[" & s - 172 & "]C)-" & Costs &""

This does not work:
teststreng = "=(SUM(R[" & s - 183 & "]C:R[" & s - 172 & "]C)-" & Costs &
")/" & Depreciation & ""


This is what teststreng is for( just pasting the value in to cells):
Worksheets("VaR").Cells((p), (q)).Activate ' p and q are counting varaibles
ActiveCell.FormulaR1C1 = teststreng


But it does accept depreciation and assigns it the right number, teststreng
accepts it but the trouble is in ActiveCell. Formula part.

Thank you:-)

"Tom Ogilvy" wrote:

I think you would get a better answer if you gave a specific example that
works and a specific example that does not work. Also, once assigned to the
variable "test", what do you intend to do with "test".

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Regards,
Tom Ogilvy


"Monika" wrote:

How do I implement: test="=(SUM(R[-181]C:R[-170]C)-string1)/string2 "in excel
VBA ?

Seems like VBA understands test="=SUM(R[-181]C:R[-170]C)-string1 but not
when dividing by one more string

HELP