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Don Guillett Don Guillett is offline
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Default Evaluating columns based on criteria

mybad

--
Don Guillett
SalesAid Software

"Don Guillett" wrote in message
...
try
mycell_Fruit = .Range(.cells(1,1),.cells(rows.count,1).End(xlup))


mycell_Fruit = .Range(.cells(1,1),.cells(rows.count.End(xlup),1))


--
Don Guillett
SalesAid Software

wrote in message
oups.com...
Can someone help with the code below and see what needs to be
changed/added? I'm getting an Object variable or With block variable
not set error on line - mycell_Fruit =
.Range(.cells(1,1),.cells(rows.count,1).End(xlup)) . This code was
posted to me yesterday from
.

Thank you


lastrow = Cells(Rows.Count, 3).End(xlUp).Row
Dim mycell_Fruit As Range
with Worksheets("sheet1")
mycell_Fruit = .Range(.cells(1,1),.cells(rows.count,1).End(xlup))
End with
For i = lastrow To 1 Step -1
bMatch = True
for j = 6 to 10
if not isempty(cells(i,j)) then
res = Application.Match(cells(i,j),mycell_Fruit,0)
if iserror(res) then
bMatch = False
exit for
end if
end if
next
if bMatch then cells(i,"E").value = "Fruit"
Next