The line that selects the columns does just that. The line that deletes the
selection deletes the selected columns. The shift to the left part simply
shifts the remaining columns to the left. That code is not necessary since
the shift to the left is the default. Note that if you delete a column, the
column to the right will move left and occupy the space where the deleted
column was. The new column will also take the column letter of the deleted
column. Perhaps that is where you are confused. In other words, if the
sheet is blank and you delete a column or group of columns, you will not see
any change at all.
Exactly what is that you want this code to do? HTH Otto
"markx" wrote in message
...
Hello,

Could someone explain to me what is the meaning of the VBA expression:
Selection.Delete Shift:=xlToLeft

Intuitively, I would suppose that it should delete the selection, but why
there is this "Shift" part coming after?

The whole part of the code I try to analyze goes like this (and it looks
like a big garbage for me):

(...)
Range("A3").Select
Range(Selection, Selection.End(xlToRight)).Select
Range(Selection, Selection.End(xlDown)).Select
Selection.Copy
Sheets("Confirmations").Select
Range("BA22").Select
Selection.PasteSpecial Paste:=xlValues, Operation:=xlNone, SkipBlanks:=
_
False, Transpose:=False
Columns("BA:BD").Select
Application.CutCopyMode = False
Selection.Delete Shift:=xlToLeft
Columns("BC:BD").Select
Selection.Delete Shift:=xlToLeft
Columns("BD:BF").Select
Selection.Delete Shift:=xlToLeft
Columns("BE:BZ").Select
Selection.Delete Shift:=xlToLeft
Range("BA22:BD55").Select
Selection.Copy
Range("A22").Select
ActiveSheet.Paste
(...)

In particular, I can't see what is the goal of selecting first BA:BD, then
BC:BD, then BD:BF and finally BE:BZ...
Is it me that don't understand something or the code should be written
differently? (hint: it's still functionning correctly and it is not
deleting the data pasted in BA22 (lines 4-8 of the code)).

Many thanks for any explanations!
Mark