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Bob Phillips[_6_] Bob Phillips[_6_] is offline
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Default Application.WorksheetFunctions

Vlookup expects the lookup table as arange, not a string, so maybe

Application.VLookup(Target.Value, Range(sNamedRange), 2, False)

--
HTH

Bob Phillips

(remove nothere from email address if mailing direct)

"AMDRIT" wrote in message
...
Hello,

I am recieving Error 2015 when I call VLookUp, anyone have any ideas why?
TIA

Lookup Table Named Range "TestLookUp"

Test Lookup
Key Value
1 Value1
2 Value2
3 Value3
4 Value4

private mChanging as boolean

Private Sub Worksheet_Change(ByVal Target As Range)

If mChanging then exit sub
If Target.Address < "$B$1" then exit sub

mChanging = true

Dim sNamedRange as string
sNamedRange =

replace(ActiveWorkbook.Names("TestLookUp").RefersT o,"=","")
If Not Application.IsError(Application.VLookup(Target.Val ue,
sNamedRange, 2, False)) Then
If Not
Application.WorksheetFunction.IsNA(Application.VLo okup(Target.Value,
sNamedRange, 2)) Then
Target.Worksheet.Range("$A$1").Formula = "VLOOKUP(""" &
target.address & """,""TestLookUp"",2)"
Else
Target.Worksheet.Range("$A$1").Formula = ""
Target.Worksheet.Range("$A$1").Value = ""
End If
End If

mChanging = false

End Sub