If it doesn't find ! in the string poz, then the Instr returns 0. Subtract 1
from that, and you are then trying to get the leftmost -1 characters. Hence,
it is invalid.

You should test it

if InStr(poz, "!") 0 Then
b=Left(poz, InStr(poz, "!") - 1)
Else
b = poz
End If


--
HTH

Bob Phillips

(remove nothere from email address if mailing direct)

"mpele" wrote in
message ...

Why the command

b=Left(poz, InStr(poz, "!") + 1)

is working and

b=Left(poz, InStr(poz, "!") - 1)

doesn't work? It say: Invalid procedure call or argument...


--
mpele
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