If Mid(str, i, strlength)
should be
If Mid(str, i, 1)

Start in position i for 1 character.

JN wrote:

Hi All,

I am trying to detect the space character in a string but my code is not
working.

Thanks for your help.
JN

sub demo()

Dim strlength As Integer
Dim str As String

str = "good morning"

strlength = Len(Trim(str))

For i = 1 To strlength
If Mid(str, i, strlength) = Chr(32) Then
MsgBox "space"
End If
Next i

End Sub

--

Dave Peterson