Force Start Row in Export
You have the routine screwed up now. Better to do it properly:
Public Sub ExportToTextFile(FName As String, _
Sep As String, SelectionOnly As Boolean)
Dim WholeLine As String
Dim FNum As Integer
Dim RowNdx As Long
Dim ColNdx As Integer
Dim StartRow As Long
Dim EndRow As Long
Dim StartCol As Integer
Dim EndCol As Integer
Dim CellValue As String
Application.ScreenUpdating = False
On Error GoTo EndMacro:
FNum = FreeFile
If SelectionOnly = True Then
With Selection
StartRow = .Cells(2,1).row
StartCol = .Cells(1).Column
EndRow = .Cells(.Cells.Count).row
EndCol = .Cells(.Cells.Count).Column
End With
Else
With ActiveSheet.UsedRange
StartRow = .Cells(2,1).row
StartCol = .Cells(1).Column
EndRow = .Cells(.Cells.Count).row
EndCol = .Cells(.Cells.Count).Column
End With
End If
Open FName For Output Access Write As #FNum
For RowNdx = StartRow To EndRow
WholeLine = ""
For ColNdx = StartCol To EndCol
If Cells(RowNdx, ColNdx).Value = "" Then
CellValue = Chr(34) & Chr(34)
Else
CellValue = Cells(RowNdx,ColNdx).Text
End If
WholeLine = WholeLine & CellValue & Sep
Next ColNdx
WholeLine = Left(WholeLine, Len(WholeLine) - Len(Sep))
Print #FNum, WholeLine
Next RowNdx
EndMacro:
On Error GoTo 0
Application.ScreenUpdating = True
Close #FNum
End Sub
--
Regards,
Tom Ogilvy
"ssjody" wrote in message
oups.com...
Nigel, That worked. This VBA Rookie thanks you! Happy New Year!
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