column loop problem??
Dim rng as Range, cell as Range
set rng = Range(cells(1,2),Cells(rows.count,2).end(xlup))
for each cell in rng
Change the 1 in 1,2 to indicate the row you want to start in.
Or if that is what you mean - that you want to find the word Record in
column 2
Dim rng1 as Range, rng as Range, cell as Range
set rng1 = Columns(2).find("Record", Lookat:=xlPart, Lookin:=xlValues)
if not rng1 is nothing then
set rng = Range(rng1,Cells(rows.count,2).end(xlup))
for each cell in rng
--
Regards,
Tom Ogilvy
"Mike" wrote in message
...
I have a spreadsheet with 3 columns. Column 1 will have various text and
will each cell will have something in it. Column two has a header of "Use
Record", this column will have values of 1, 0 or it will be empty.
What I want to do is find Use "Record" and then work my way down the
column
and if the value = 0 then make column 1 text = "Dropped" then bold the
whole
row.
How do I do the loop since column 2 could have a blank cell and there
still
could be rows in the spreasheet?
Thanks
Mike
Col1 Use Record Col2
a 1
b 0
c
d 0
e 0
f
g 1
h
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