No. Try the following (no guarantees!) instead of 8 in your denominator:

(Columns("P:P").Width / Columns("P:P").ColumnWidth)

--

Vasant


"StevenS" wrote in message
...
Is this the correct code to size a cell to the size of a users screen no
matter what the size
'eg
Columns("p:p").ColumnWidth = ActiveWindow.VisibleRange.Width / 8 (8 =
factor
to convert to pixels)
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SS