"Harlan Grove" wrote in message
ups.com...
Sandy Mann wrote...
To convert the assessment in, say cell F20, to the appropriate number try:
=3*(CODE(F20)-48)-(2-(CODE(UPPER(RIGHT(F20)))-65))
ie 5c will be converted to 15
...
Alternatively,
=3*LEFT(F20,1)-SEARCH(MID(F20,2,1),"cba")+1
which has the added advantage of catching invalid entries. If F20
contained "9x", this formula would return #VALUE! rather than 48.
You forgot to say - and with one fewer function call - you must be slipping
<g
--
Regards
Sandy
Replace@mailinator with @tiscali.co.uk