Suppose D6 contains the date, June 4, 2005 and D9 contains the date, July 4,
2003.

The formula is:

=365*(Year(D6)-Year(D9))+Date(2003,Month(D6),if(And(Month(D6)=2,D ay(D6)=29),28,Day(D6)))-Date(2003,Month(D9),If(And(Month(D9)=2,Day(D9)=29) ,28,Day(D9)))

In the formula you can use any year for "2003", as long as it's a leap year.

If you always want a positive result, you can wrap ABS() around the formula
so that the order of the two dates is immaterial.

"kckar" wrote:


is there a formula where i can exclude a date (february 29) that occurs
between two given dates

so that whenever a leap year occurs it doesnt calculate it into days
between two dates

ex when you subtract 06/04/2005-07/04/2003=701 because that includes
the leap year
i want to be able to take out february 29 (2004 was a leap year so that
it equals 700)

i was thinking something like the networkindays function but instead of
excluding weekends and holidays you include them and only exclude
february 29


--
kckar
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