variable for columns(??).property
Thanks Vasant,
In my real code I dim the vars properly. For this example, since I use
option explicit I just dimmed them as varants for 'speed of typing'.
Also, because I use a lot of variables for columns and rows, i'm in the
habit of using the numbers rather than letters so I don't have to convert
a 1 into an "A".
Thanks again,
Neal
"Vasant Nanavati" wrote:
Try:
first = "M"
last = "O"
BTW, you should declare the correct data types for your variables; i.e.:
Dim first As String, last As String, workrange As String
--
Vasant
--
Vasant
"Neal Zimm" wrote in message
...
With your help a while ago I was able to 'vary' the rows being
procecessed.
the rows procedure works, I could not get the columns procedure to work.
sub variable_rows()
''' this works
Dim first, last, hiderange
first = 13
last = 15
hiderange = first & ":" & last
Rows(hiderange).Hidden = True
End Sub
Sub variable_columns()
'''this does not work, object error
Dim first, last, workrange
first = 13
last = 15
workrange = first & ":" & last
Columns(workrange).ColumnWidth = 20
End Sub
Help Please.
thanks.
--
Neal Z
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