Could you give examples of what you start with and what you want to end up
with. Show potential locations of your string's ", , "
Still need to loose any trailing comma, and possible trailing space?
JE's & my formulas appear to do same, as his is far more elegant probably
best to try and develop his. However I suspect a solution will be much
easier with a macro, assuming it's even possible with a worksheet formula.
Regards,
Peter T
"David Godinger" wrote in message
...
"Peter T" <peter_t@discussions wrote:
=LEFT(SUBSTITUTE(A1,", , ",""),IF(RIGHT(SUBSTITUTE(A1,", ,
",""))=",",LEN(SUBSTITUTE(A1,", , ",""))-1,LEN(SUBSTITUTE(A1,", ,
",""))))
This does almost everything I want, but I made a mistake in expressing
myself. I don't want to be left with nothing. I always want to leave one
instance of ", "
Whether I'm substituting ", , , , , " or ", , " I always want to be left
with ", "
Thanks again if you have the time.
on one line
Peter T
I'd like to make a formula (NOT USING VBA) that would replace, in a
list
of
characters, all instances of the following with nothing:
, ,
(That's a comma followed by a space, followed by a comma, followed by
a
space.)
If possible, the formula would also eliminate the last character in
the
string if it's a comma.
Thanks,
Dave
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