Actually, didn't need that first Row() function:

=INDEX($A$1:$A$100,100-(ROW()-1))

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Regards,

RD
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Please keep all correspondence within the Group, so all may benefit!
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"RagDyer" wrote in message
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Another formula approach which is *not* dynamic.
But if you know the size of your list, it's short and sweet!<g

With data starting in A1, try this in B1, and copy down to the end:

=INDEX($A$1:$A$100,ROW($A$100)-(ROW()-1))
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HTH,

RD
==============================================
Please keep all correspondence within the Group, so all may benefit!
==============================================

"Max" wrote in message
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Assume source data is in col A, in row1 down
Fill sequential numbers; 1,2,3,... in B1 down
Select cols A & B, do a Data Sort by col B descending

or one play if you need it dynamic ..
put in B1: =ROWS($A$1:A1)
put in C1:


=IF(INDEX(A:A,MATCH(LARGE(B:B,ROWS($A$1:A1)),B:B,0 ))=0,"",INDEX(A:A,MATCH(LA
RGE(B:B,ROWS($A$1:A1)),B:B,0)))
Select B1:C1, fill down until the last row of data in col A
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Rgds
Max
xl 97
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xdemechanik <atyahoo<dotcom
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"Ken Hardman" <Ken wrote in message
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?
How do I reverse the order (sequence) of a column of data in Excel