Thanks a lot for this Bernie. It works fine and your code is much more
neat and efficient than my code.
The only problem that I've got left is that there are still multiple
company names in the list (e.g. name1 occurs 3 times).
Do you think it is possible to create the same list but only with the
top 50 pairs where each pair consists of 2 different companies that are
not part of any of the other pairs?

Thanks again,
Manuel