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ScottO
 
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The syntax of your formula looks right, so my guess is that the value in C2
doesn't exist in the range 'March 2005'!A2:A187 ... but I'm sure that you've
already checked for that.
I don't have any other suggestions.
Rgds,
ScottO

"jjjam" wrote in message
...
| ScottO,
| ...the result is coming up as #N/A. Am I doing something wrong?
(obviously
| YES).....
|
| =INDEX('March 2005'!D2:D187,MATCH(C2,'March 2005'!A2:A187,0))
|
| "ScottO" wrote:
|
| Yes.
| Put this in G2
| =INDEX($D$2:$D$50,MATCH(C2,$A$2:$A$50,0))
| Rgds,
| ScottO
|
| "jjjam" wrote in message
| ...
| | Would it be possible to modify the formula below to include the
following
| | logic when a match is found?
| | Example:
| | If the match to C2 is found in cell $A$15, take cell $D$15 and place
it in
| G2.
| |
| |
| |
| | "jjjam" wrote:
| |
| | That's the ticket!...thanks.
| |
| | "ScottO" wrote:
| |
| | Try this in F2 ...
| |
| | =IF(ISNA(MATCH(C2,$A$2:$A$50,0)),"N","Y")
| |
| | Rgds,
| | ScottO
| |
| | "jjjam" wrote in message
| | ...
| | | Simple question but I'm stumped. How do I write a formula that
will
| take
| | a
| | | value from a cell (C2), scan a column (A2:A50) for the value in
C2,
| then
| | put
| | | a Y or a N in F2 if the value is found (Y) or not found (N).
| | |
| | |
| |
| |
| |
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