Making Workbook_Open macro conditional
Oops, got it backwards, but hope you get the idea...
"K Dales" wrote:
Nothing happens to trigger your code before the Workbook_Open event; you
would need to approach it like this:
Sub Workbook_Open()
If ThisWorkbook.Name = "MyFileName.xls" Then
' Call your procedure here
Else
' existing Workbook_Open code here
End If
End Sub
"nospaminlich" wrote:
I have a file with a Workbook_Open macro (see below) but there is another
macro which enables the user to save the most worksheets in the file with a
new name. The new file retains the Workbook_Open macro which I don't want
not least because the Worksheet "Menu" referred to has been deleted so keps
coming up with an error.
I've tried including code to remove the Workbook_Open macro before saving as
a new file without success but thought this may be an easier way.
Is it possible to make the Workbook_Open macro conditional by adding code
like
If this file is called myfilename.xls
Then
(add Workbook_Open macro code here)
Else
End Sub
If so, what is the correct syntax
Thanks in anticipation
Keith
-----------
Private Sub Workbook_Open()
ThisWorkbook.Activate
Application.Calculation = xlCalculationManual
Sheets("Menu").Select
End Sub
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