Use function InStr():
InStr(1, "chair", "*") returns 0 bcause * isn't found in "chair";
InStr(1, "chair", "h") returns 2, because h is found in the second position
in "chair" starting from 1.
HTH,
Nikos
"ajitpalsingh200" wrote in
message ...
Is there any way to check whether string "chair" contains "*" or not?
thankx in advance
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ajitpalsingh200
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