Removing leading spaces
JM,
If they are really spaces, and you don't have any interior spaces to worry
about, then you could use the line:
Columns("O:O").Replace What:=" ", Replacement:="", LookAt:=xlPart
Otherwise, you will need to re-record a macro that does what you need it to
do.
HTH,
Bernie
MS Excel MVP
"jmdaniel" wrote in message
...
I am converting an Oracle report to Excel, and have run into an issue. I
have
changed the macro to pull a different column than before. The data still
resides in the O column, but is different, from a trailing and leading
zero
standpoint. The portion of the macro that worked befo
' Removes leading spaces column O
Columns("O:O").TextToColumns Destination:=Range("O1"), _
DataType:=xlFixedWidth, OtherChar:="|", _
FieldInfo:=Array(Array(0, 2), Array(7, 1))
the cells in this column had 6 leading, and 4 trailing spaces. Now, when I
pull a different column of data from Oracle, but put it in the same column
in
Oracle, I get the "Do you want to replace the contents of the destination
cells?" question, which I did not get before. If I answer yes, it errors
out
on the next step in the macro, which attempts to put the data in a pivot
table format. It won't work, because the macro has deleted the column
heading. Again, something that didn't happen before. The onle difference I
can see is that the new column I am trying to bring in has 6 preceding
spaces, no trailing, instead of the 6 leading and 4 trailing of the old
column. Evidently, I am clueless, and could use a hand....
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