When solving for an exponent, take the log of both sides.

X = (p)(a) (i^n)
X/pa=i^n
log (X/pa)=n log (i)
n=log(x/pa)/log(i)

You get the idea.

"sirsoto" wrote:

Hello,

In the following formula, I want to determine "n" which is an exponent

X - [(p)(a)(i^n)] = 0
X = (p)(a)[(1+i)^n]

I tried to use the seriessum function, but "n" is a required input. Which
function do I use to solve for n? Thank you.