View Single Post
  #5   Report Post  
Posted to microsoft.public.excel.programming
john john is offline
external usenet poster
 
Posts: 97
Default Chip's ColorIndexOfCF Function

Chip, thanks for the response - got it to work.

By the way, thanks for your site. It's a great reference
tool.

John Mansfield

-----Original Message-----
John,

The ColorIndexOfCF is a normal VBA function, not a

worksheet
function. Thus, you don't call it as a method of your fn
variable.

Change

If fn.ColorIndexOfCF(Rng1) = 6 Then
' to
If ColorIndexOfCF(Rng1) = 6 Then

Secondly, you are probably passing the wrong variable to

the
ColorIndexOfCF function. Pass Cell rather than Rng1


--
Cordially,
Chip Pearson
Microsoft MVP - Excel
Pearson Software Consulting, LLC
www.cpearson.com




"John" wrote in

message
...
I've added Chip Pearson's ColorIndexOfCF Function to the
following conditional formatting code below.

I'm getting an "object doesn't support property or

method
error" on the following line:

" If fn.ColorIndexOfCF(Rng1) = 6 Then "

What I'm trying to do is loop through a range and

say "If
the conditional formatting color index = 6 (yellow)
then "X" else "Y".

How can I restructure the code below to make it work?

Sub Test()

Set Rng1 = Range("B4:B10")
Set Rng2 = Range("F4")
Set fn = Application.WorksheetFunction

For Each Cell In Rng1
If fn.ColorIndexOfCF(Rng1) = 6 Then
Cell.Copy
Rng2.PasteSpecial Paste:=xlValues
Set Rng2 = Rng2.Offset(1, 0)
End If
Next Cell

End Sub

Chip's function reference:
http://www.cpearson.com/excel/CFColors.htm




.