M18 is a total of M7 and M8 giving the total for the 2 weeks. I charge
£150 for one week and £250 for 2 weeks rental, a discount of £50 I (through
lack of computing skills) find it easier this way, the sum total is the
same.
I will give your formula a try.

thanks

"JE McGimpsey" wrote in message
...
Your problem statement is a bit ambiguous. You say M7 should equal 150
if one week only, and M8 should equal 100 if two weeks. But what should
M7 equal if two weeks?

Perhaps this will work:

M7: 150
M8: =100 * ((DATE(E7,D7,C7)-DATE(E6,D6,C6))7)




In article ,
"Scudo" wrote:

I want to change how this works, I messed around a little but no joy.

In cells C6,D6,E6 I have words date, month, year, In cells G6,H6,I6 I
have words date, month, year,
In cells C7,D7,E7 Date is entered dd/mm/yy, In cells G7,H7,I7
Date is entered dd/mm/yy

The idea is a start date and a finish date, It is based on renting a
property and will be either one week or two weeks

If the dates equal one week only then I wish cell M7 to print £150
If the dates equal 2 weeks then cell M8 to equal £100

Thus giving a combined total of £250 for two weeks rental. (which is
later
added together in another cell)

The formula at the moment in cell M7 is
=CHOOSE(MATCH(D7,{0;5;7;9},1),"",150,200,"")
The formula in cell M8 at the moment is
=CHOOSE(MATCH(H7,{0;5;7;11},1),"",125,150,"")
I previously wanted the formula to work on a `depending on month`basis

I hope this is clear.
thanks