If the number fails, then try it again as text.

Dim loanorig As Variant
Dim loanorigrow As Variant
Dim rng As Range
Set rng = Range("a1:a5")

For i = 1 To 3
loanorig = Range("c" & i).Value

If IsNumeric(loanorig) Then
loanorigrow = Application.Match(CDbl(loanorig), rng, 0)
if iserror(loanorigrow) then
loanorigrow = Application.Match(loanorig,rng,0)
End if
Else
loanorigrow = Application.Match(loanorig, rng, 0)
End If

If IsError(loanorigrow) Then
MsgBox "No match made"
Else
Range("e" & i) = loanorigrow
End If

Next i

if you have a text 89 and a number 89, the number 89 will win.

--
Regards,
Tom Ogilvy





"mike allen" wrote in message
...
i posted this last week and have since found a problem with it. this is a
very small sample of the main array:

123
abc
#345
67#
'89

some are text, some are numbers; the problem is the one that looks like a
number (isnumeric), but is actually text: '89, the last one.

if i have a seperate list of (important that in this case, they all have '
in front (text):

'67#
'123
'89

i want to know what row in the array (which starts on row1) each of these
are in. the answers should be: 4, 1, 5.

this is the code that gets: 4, 1, "no match made", which is errroneous.

Dim loanorig As Variant
Dim loanorigrow As Variant
Dim rng As Range
Set rng = Range("a1:a5")

For i = 1 To 3
loanorig = Range("c" & i).Value

If IsNumeric(loanorig) Then
loanorigrow = Application.Match(CDbl(loanorig), rng, 0)
Else
loanorigrow = Application.Match(loanorig, rng, 0)
End If

If IsError(loanorigrow) Then
MsgBox "No match made"
Else
Range("e" & i) = loanorigrow
End If

Next i

the old problem was if the apparent match in the array truely was a
number,
i had to change my field to be compared to a number if it was numeric
(could
be converted to number). this is what tom ogilvy came up w/ last time,
and
it worked. the new problem arises when the apparent match in the array
looks like a number, but is text. any thoughts? thanks, mike allen