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Bob Flanagan Bob Flanagan is offline
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Default trouble with a listindex value...

Change

SelectedQA = SelectedQA & .ListIndex + 1

to

SelectedQA = SelectedQA & iCt + 1

Robert Flanagan
Macro Systems
Delaware, U.S. 302-234-9857
http://www.add-ins.com
Productivity add-ins and downloadable books on VB macros for Excel

"Paul" wrote in message
...
Help!

Using XL 2000, I'm trying to assign and show a listindex
value to an item selected in the list.
Although the procedure is relatively simple, I have added
the code i'm currently using to help explain what is going
on.

I have a listbox on userform1 which is populated thus:

ListBox1.Clear
With ListBox1
.RowSource = "Info!A1:A12"
.MultiSelect = fmMultiSelectMulti
.ListStyle = fmListStyleOption
End With

I can then scroll through the listbox which contains 16
items to select one or many. When selected, I need the
listindex value to be appended to a list (assuming more
than one item is selected) which is then displayed in the
worksheets activecell.

The following does not quite fulfil this requirement as
the active cell only appends the previous listindex value.
if items 1,3,5,9 were selected (or at least their
equivelant listbox text, activell shows 9,9,9,9 - the
previous 3 were overwritten.

Private Sub ListBox1_Change()
SelectedQA = ""
With ListBox1
For iCt = 0 To .ListCount - 1
If .Selected(iCt) = True Then _
SelectedQA = SelectedQA & .ListIndex + 1
_& ", "
Next iCt
End With

If Len(SelectedQA) 0 Then _
SelectedQA = Left(SelectedQA, Len(SelectedQA))
ActiveCell = SelectedQA '
End Sub

I hope this explains my problem.
Any solutions/guidance appreciated.

Thanks, Paul