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Phil Phil is offline
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Default use vb to delete marked rows

Great. I never thought about it like that, work with the sum. Also didn't
think of working from the bottom up. I'm a vb novice, but am familar with
the for next. Thanks alot, I'll do some playing around with. Thanks.

Paul D wrote:
How about the sumif function
=SUMIF(J3:J700,"<X",I3:I700)

If you really want to delete the rows, use a for next loop and start
at the bottom and work up.
Paul D

"Phil" wrote in message
...
I never used the autofilter so going thru the help files now. One
question I have is in the cells in column I we have numbers that get
totaled at the end. If I use autofilter to hides all the rows marked
with X will my total still add all the values from I3:I700 including
the hidden ones? I don't want it to. When I mark it with an X and it
hides I need those values in cells I3:I700 to not add into the
total. That's why I thought just deleting those rows was the way to
go. The total formula is: =sum(I3:I700) Basicly I'm saying I want
to mark rows that I don't want to add into the total. However that
is accomplished doesn't matter either deleting or hiding the rows.
Thanks.

Don Guillett wrote:
Why not use dataautofilterfilter on x and delete all rows. Record
a macro if desired


Having trouble with this one, hope someone can help me with the
code. I have a sheet with rows 3-700 and columns A-J. I want to
have some vb code that when run(doing it on a click action for a
button) deletes rows that I have marked with an X in cell J3-J700.
So if it sees a X in cell J3, it highlights the entire row and
deletes it, then move on to J4 and checks for the X and so on. If
there is no X then it should just move to the next one and keep
checking.
I can get it to sort of work with if/then statements, but one
problem I'm having is when you delete a row they all shift up, so
just going to the next row starts to "skip" rows that were moved
up. And the other problem is how to simplify the code for J3-J700
so I don't have to put 700 if/then statements in. Thanks for any
help.