Thread: If-Then in VBA
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ryan ryan is offline
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Default If-Then in VBA

where do you declare a value for the variable check312

----- wrote: ----

Thanks but it is not workin

Icannot figure out wh
-----Original Message----
Try this
Sub manual312(
Sheets("Reimbursement Sheet Global").Selec

If check312 = 0 The
Range("R32").Selec
ActiveCell.FormulaR1C1 = Medicare_payment_312 * 1.
En
Els
If check312 0 The
Range("R32").Selec
ActiveCell.FormulaR1C1 =
"=(R[-25]C[4]*R[-25]C)+(R[-23]C[4]*R[-23]C)+(R[-21


[4]*R[-21]C)
Range("R34").Selec
En
End I
End I
End Su
-----Original Message----

I am trying to create a button that will evaluate a cell
and based upon its value, enter one of 2 formulas. after
writing the code, it keeps returning a value that it
should notand I can't figure why
Here is the Attached cod
Sub manual312(


' manual312 Macr
' Macro recorded 4/15/2004 by jminke

Sheets("Reimbursement Sheet Global").Selec
If check312 = 0 The

Range("R32").Selec
ActiveCell.FormulaR1C1 = Medicare_payment_312 * 1.
ElseIf check312 0 The
Range("R32").Selec
ActiveCell.FormulaR1C1 =

"=(R[-25]C[4]*R[-25]C)+(R[-23]C[4]*R[-23]C)+(R[

21
C[4]*R[-21]C)
Range("R34").Selec
End I


End Su
The problem arises in that the check312 cell is 0 and I

am getting the first formula.
Please hel