What line of code is causing the error. Post your code.


--
Cordially,
Chip Pearson
Microsoft MVP - Excel
Pearson Software Consulting, LLC
www.cpearson.com


"jim" wrote in message
...
I get runtime error 424
object required
with that case statement.


"Chip Pearson" wrote in message
...
Jim

You want to use the Address property to determine which cell
you
are working with in the For Each loop. For example,

For Each cell In FormulaRange
Select Case Cell.Address(False,False)
Case "E8"
formulatest = "=E9+C8"
Case "E9"
' etc
End Select
If cell.Formula = formulatest Then
' same formula
Else
' different formula
End If
Next cell


--
Cordially,
Chip Pearson
Microsoft MVP - Excel
Pearson Software Consulting, LLC
www.cpearson.com


"jim" wrote in message
...
I have the formula in the code. I need to be able to
reference
the formula
in the cell and compare it to a string containing the
formula.
Each cell
has a different formula. I was tring to us a case for the
cell
like this.

formularange = Worksheets("Testing Sheet").Range("e8: f25 )

For Each cell In formularange



For Each cell In formularange

Select Case cell

Case e8
formulatest = "=E9+C8"
Case e9
formulatest = "=E10+C9"
End Select

If cell.Formula = formulatest Then
Response = MsgBox(cell.Formula & vbNewLine &
formulatest)
Else
Response = MsgBox(cell.Formula & vbNewLine &
formulatest)
End If

The message boxes were just for testing purposes, but the
problem is with
the if statement.

"jim" wrote in message
...
I would like to be able to check to see if a formula has
been
modified. I
need to do this for a lot of cells, so I am trying to use
a
loop, but I am
having no luck. Any ideas?