Thanks for letting me know.

AfterUpdate is good, it's an oft overlooked event.

--

HTH

Bob Phillips
... looking out across Poole Harbour to the Purbecks
(remove nothere from the email address if mailing direct)

"Martin Koenig" wrote in message
om...
Hi Bob,

Probably not the most elegant solution, I just moved the Code to
Afterupdate, but it works.

Martin

"Bob Phillips" wrote in message
...
It's a pleasure Martin.

What did you go with on point 2 in the end?

--

HTH

Bob Phillips
... looking out across Poole Harbour to the Purbecks
(remove nothere from the email address if mailing direct)

"Martin Koenig" wrote in message
om...
Bob,
Just wanted to say thanks for your help.
Kind Regards
Martin

"Bob Phillips" wrote in message
...
1. txtSFA.Text = rng(cmbAWS.ListIndex + 1)(1, 2).Text

2. Add a command button, and calculate upon clicking the button
rather
than
textbox change. The problem with textbox change is that it fires for
every
change to the textbox, not just when done. You could also experiment
with
the textbox Exit, or AfterUpdate events.

--

HTH

Bob Phillips
... looking out across Poole Harbour to the Purbecks
(remove nothere from the email address if mailing direct)

"Martin Koenig" wrote in message
om...
1. Textbox Number Format

Based on a combobox selection a textbox is filled as shown below:

Private Sub cmbAWS_Change()
Set rng = Range(cmbAWS.RowSource)
txtSFA.Text = rng(cmbAWS.ListIndex + 1)(1, 2)
End sub

The value that is supposed to be read in to the textbox from the
worksheet is sometimes a single decimal (5.1) or a two decimal
(5.10)number depending on the combobox selection, but the value
displayed is always a single decimal(5.1).

How can I get the textbox to display what is shown on the
worksheet
(5.1 or 5.10)?

2. Deleting Value from Textbox

The user is to enter a value and based on the value entered in the
textbox txtDefectLength, it will use a dimension which had been
previously entered into the worksheet(rng3) to calculate percent
of of
defect.

Private Sub txtDefectLength_Change()
Dim rng1 As Range
Set rng1 = Worksheets("WPQ").Range("CD24")
txtPrecentDefect.Value = (((txtDefectLength.Value) / (rng3 /
4))
* 100)
If txtPrecentDefect.Text <= 10 Then
txtResults.Value = "Passed"
Else: txtResults.Value = "Failes"
End If
End Sub

When entering a value into the textbox(txtDefectLength) it works
fine,
but if the text is deleted to enter a different value I become the
error message "Type mismatch (Error 13)"

What can I do to stop this from happening?

Any help would be appreciated.

Kind Regards
Martin