Ron,

Insert these 2 lines

SearchString = Left(SearchString, sStart - 1) & Right(SearchString,
Len(SearchString) - sEnd)
ActiveCell.Value = SearchString


--

HTH

Bob Phillips
... looking out across Poole Harbour to the Purbecks
(remove nothere from the email address if mailing direct)

"Ron " wrote in message
...
Hi,

I need some help with my code please.
I am attempting to loop though all the cells in a column and delete the
characters within a set of parentheses including the parentheses. I
want the user to verify the string before deletion using a message box.
I am also open to any suggestions to improve the code.

Thanks.
Ron

Sub DeleteRefNo()

Dim SearchString As String
Dim SearchChar1 As String
Dim SearchChar2 As String
Dim sStart As String
Dim sEnd As String
Dim rCount As Integer
Dim dString As String
Dim length As Integer

rCount = 2

Do

Cells(rCount, 4).Select

SearchString = ActiveCell.Value
SearchChar1 = "("
SearchChar2 = ")"

'cycle through search string
For X = 1 To Len(SearchString)

sStart = InStr(1, SearchString, SearchChar1, 1)
sEnd = InStr(1, SearchString, SearchChar2, 1)

If sStart < 0 And sEnd < 0 Then
length = sEnd - sStart + 1
dString = Mid(SearchString, sStart, length)
MsgBox ("Delete string? " & dString), vbYesNo
If vbYes Then
'????? statement to delete the string in dString ???????
End If
End If

Next X

rCount = rCount + 1

Loop Until IsEmpty(ActiveCell.Offset(1, 0))

Cells(1, 1).Select

End Sub


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