View Single Post
  #9   Report Post  
Posted to microsoft.public.excel.programming
Norman Harker Norman Harker is offline
external usenet poster
 
Posts: 162
Default DateDiff("w") -- problem

Hi zSplash!

You and me both! I was misled by the intro description and didn't look
closer until I got the same results that you did.

Last resort? Read The Fine Manual.

See you around the newsgroups.

--
Regards
Norman Harker MVP (Excel)
Sydney, Australia

Excel and Word Function Lists (Classifications, Syntax and Arguments)
available free to good homes.
"zSplash" wrote in message
...
Thanks, Norman, for the help. I guess I just didn't read the

expanded help,
and assumed. Sorry.

So, how do I access (or install, if necessary) the "Analysis

Toolpack"
functions? This is new to me. (I don't see it in my References...)

st.

"Norman Harker" wrote in message
...
Hi zSplash!

I think that you are misunderstanding what DATEDIFF means by "w"

and
"ww" arguments.

Extract from Help:

When interval is Weekday ("w"), DateDiff returns the number of

weeks
between the two dates. If date1 falls on a Monday, DateDiff counts

the
number of Mondays until date2. It counts date2 but not date1. If
interval is Week ("ww"), however, the DateDiff function returns

the
number of calendar weeks between the two dates.

Both are counting weeks which is why in your case you are getting

the
same answer.

To count weekdays use the Analysis ToolPak NETWORKDAYS function.

--
Regards
Norman Harker MVP (Excel)
Sydney, Australia

Excel and Word Function Lists (Classifications, Syntax and

Arguments)
available free to good homes.
"zSplash" wrote in message
...
I am trying to count weekdays, using the "w" argument

unsuccessfully. I get
the same value for "w" (weekday) as I do for "ww" (week). What

am I
doing
wrong?
Code:
estDays=DateDiff("w", ufm1.Calendar1, ufm1.Calendar2)

TIA