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Todd Huttenstine\(Remote\) Todd Huttenstine\(Remote\) is offline
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Posts: 10
Default Match Function(Code modification)

thanx

it worked.


"Nigel" wrote in message
...
correction in line 2 to read "IV1" not "B1"


If Application.CountIf(Range("IV1:IV100"), Range("A4")) 0 Then
Range("area22").Interior.ColorIndex =

Range("IV1").Interior.ColorIndex
Else
Range("area22").Interior.ColorIndex = 2
End If


"Nigel" wrote in message
...
Todd, try this

If Application.CountIf(Range("IV1:IV100"), Range("A4")) 0 Then
Range("area22").Interior.ColorIndex =

Range("B1").Interior.ColorIndex
Else
Range("area22").Interior.ColorIndex = 2
End If

Cheers
N


"Todd Huttenstine(Remote)" wrote in

message
...
Hey guys,

If Application.CountIf(.Range("IV1:IV100"), "Add Stat Name Here") 0

Then
Range("area22").Interior.ColorIndex =
Range("IV1").Interior.ColorIndex
Else
Range("area22").Interior.ColorIndex = 2
End If

Above is a working code that will color a Named Range of cells a

specified
color if the value "Productivity" is found in Range ("IV1:IV100"). In

this
example the named range is "area22" and the specified color is

associated
with the variable "Range("IV1").Interior.ColorIndex". Also in this

example
the Value "Productivity is located in cell A4. If the value

"Productivity"
is not found in Range ("IV1:IV100"), then Range "area22" will be

shaded
color 2.

In the above example, in order for the code to work, you must specify

what
value to look for in Range ("IV1:IV100"). Instead, what I would like

is
for
the code to look in Range ("IV1:IV100") and if it finds the value of

cell
A4, then color Range "area22" the variable
"Range("IV1").Interior.ColorIndex". If it does not find the value,

then
color Range "area22" color 2.


Thank you


Todd Huttenstine






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