![]() |
not sure if I'm using the correct formula for the result I want
I'm trying to calculate a 'low net' score. A persons 'actual score' minus
'their handicap' = 'low net' score. I have this worksheet setup like this; A4:A23 = list of names Columns B-U have the weekly calculated low net scores B4:U23 = the calculated 'low net' scores using this formula =SUM(Scorecard!B4-Scorecard!Y4); (this is for player one) Scorecard!B4 is player one's first week 'actual score', Scorecard!Y4 is player one's calculated 'handicap'. In Row B25:U25 I have this formula {=MIN(IF(B$4:B$230,B$4:B$23))}, to pull the lowest score of all persons for that week. My problem is this; I'm getting the #DIV/0 error and I don't know how to get around that because we do have occational zero's "0" for scores when people don't show up. The error is coming from my "handicap" formula =((SUM(B4:C4)/COUNTIF(B4:C4,"0"))-36)*0.8 I have two bits of data to work around; How can I write a formula to work above zero AND ignore the #DIV/0 cells? I'm referring to B25:U25 formula. Thanks, Brad |
not sure if I'm using the correct formula for the result I want
Hi,
Please only post a question once. For the answer to this see your previous post. -- If this helps, please click the Yes button. Cheers, Shane Devenshire "Brad" wrote: I'm trying to calculate a 'low net' score. A persons 'actual score' minus 'their handicap' = 'low net' score. I have this worksheet setup like this; A4:A23 = list of names Columns B-U have the weekly calculated low net scores B4:U23 = the calculated 'low net' scores using this formula =SUM(Scorecard!B4-Scorecard!Y4); (this is for player one) Scorecard!B4 is player one's first week 'actual score', Scorecard!Y4 is player one's calculated 'handicap'. In Row B25:U25 I have this formula {=MIN(IF(B$4:B$230,B$4:B$23))}, to pull the lowest score of all persons for that week. My problem is this; I'm getting the #DIV/0 error and I don't know how to get around that because we do have occational zero's "0" for scores when people don't show up. The error is coming from my "handicap" formula =((SUM(B4:C4)/COUNTIF(B4:C4,"0"))-36)*0.8 I have two bits of data to work around; How can I write a formula to work above zero AND ignore the #DIV/0 cells? I'm referring to B25:U25 formula. Thanks, Brad |
not sure if I'm using the correct formula for the result I want
SORRY!
I didn't mean to post twice...after sending, it got stuck in my outbox. While trying to fix the issue I inadvertantly sent it twice. "Shane Devenshire" wrote in message ... Hi, Please only post a question once. For the answer to this see your previous post. -- If this helps, please click the Yes button. Cheers, Shane Devenshire "Brad" wrote: I'm trying to calculate a 'low net' score. A persons 'actual score' minus 'their handicap' = 'low net' score. I have this worksheet setup like this; A4:A23 = list of names Columns B-U have the weekly calculated low net scores B4:U23 = the calculated 'low net' scores using this formula =SUM(Scorecard!B4-Scorecard!Y4); (this is for player one) Scorecard!B4 is player one's first week 'actual score', Scorecard!Y4 is player one's calculated 'handicap'. In Row B25:U25 I have this formula {=MIN(IF(B$4:B$230,B$4:B$23))}, to pull the lowest score of all persons for that week. My problem is this; I'm getting the #DIV/0 error and I don't know how to get around that because we do have occational zero's "0" for scores when people don't show up. The error is coming from my "handicap" formula =((SUM(B4:C4)/COUNTIF(B4:C4,"0"))-36)*0.8 I have two bits of data to work around; How can I write a formula to work above zero AND ignore the #DIV/0 cells? I'm referring to B25:U25 formula. Thanks, Brad |
All times are GMT +1. The time now is 02:41 AM. |
Powered by vBulletin® Copyright ©2000 - 2025, Jelsoft Enterprises Ltd.
ExcelBanter.com