I'm trying to convert a rather complicated formula into a custom
function.

Effectively, what the function does is it takes two values and uses the
worksheet function Match to locate the position of the values from a
sequentially increasing set in a range that are just smaller than the
two values being tested and then makes a comparison of those two
location values.

E.g. A = Match(value1, range1,1), B= Match(value2,range1,1); C = B - A

There are different procedures dependent on whether C = 0, 1, or is
greater than 1.
In each case, the procedure requires (in the workbook formula, not the
custom function - yet?)
the use of an offset function applied to another range of values
(range2) of similar length to range1. I do this by using the reference
cell that is the first in the range of range2 and the offset a certain
distance based on the values of A,B, and C and then perform some simple
math functions.

How do I reference the first cell location in range2 and use the offset
formula within a custom function? I'm using the
Application.WorksheetFunction.Offset, but it doesn't seem to work.

Thoughts?

Have you tried using the VBA Find Method to locate the value in Range 2?

From the help file (you'll obviously want to modify it to suit):

With Worksheets(1).Range("a1:a500")
Set c = .Find(2, lookin:=xlValues)
If Not c Is Nothing Then
firstAddress = c.Address
Do
c.Interior.Pattern = xlPatternGray50
Set c = .FindNext(c)
Loop While Not c Is Nothing And c.Address < firstAddress
End If
End With

" wrote:

I'm trying to convert a rather complicated formula into a custom
function.

Effectively, what the function does is it takes two values and uses the
worksheet function Match to locate the position of the values from a
sequentially increasing set in a range that are just smaller than the
two values being tested and then makes a comparison of those two
location values.

E.g. A = Match(value1, range1,1), B= Match(value2,range1,1); C = B - A

There are different procedures dependent on whether C = 0, 1, or is
greater than 1.
In each case, the procedure requires (in the workbook formula, not the
custom function - yet?)
the use of an offset function applied to another range of values
(range2) of similar length to range1. I do this by using the reference
cell that is the first in the range of range2 and the offset a certain
distance based on the values of A,B, and C and then perform some simple
math functions.

How do I reference the first cell location in range2 and use the offset
formula within a custom function? I'm using the
Application.WorksheetFunction.Offset, but it doesn't seem to work.

Thoughts?

VBA has its own offset method.

Range("A1").Offset(3, 0)
refers to cell A4 ( Offset(0,0) is cell A1)

Range("A1") (4, 1)
also refers to cell A4 (cell A1 is 1,1 so the row and column offset will be
1 more than if you use the offset method shown above)

With Worksheets("Sheet1")
.Range("A1", .Range("A1").Offset(3,0))
End With

refers to Sheet1!A1:A4




" wrote:

I'm trying to convert a rather complicated formula into a custom
function.

Effectively, what the function does is it takes two values and uses the
worksheet function Match to locate the position of the values from a
sequentially increasing set in a range that are just smaller than the
two values being tested and then makes a comparison of those two
location values.

E.g. A = Match(value1, range1,1), B= Match(value2,range1,1); C = B - A

There are different procedures dependent on whether C = 0, 1, or is
greater than 1.
In each case, the procedure requires (in the workbook formula, not the
custom function - yet?)
the use of an offset function applied to another range of values
(range2) of similar length to range1. I do this by using the reference
cell that is the first in the range of range2 and the offset a certain
distance based on the values of A,B, and C and then perform some simple
math functions.

How do I reference the first cell location in range2 and use the offset
formula within a custom function? I'm using the
Application.WorksheetFunction.Offset, but it doesn't seem to work.

Thoughts?