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using =sum() to get a percentage
I recently received a spreadsheet that contained =sum(a1/a2)-1+1. The
cell containing the formula was formatted to percentage. I was wondering why use =sum()-1+1 when +a1/a2 would render the same result (provided the cell is formatted to percentage)? Thank you |
using =sum() to get a percentage
The author of the workbook you received is a pervert.
:-) -- AP a écrit dans le message de news: ... I recently received a spreadsheet that contained =sum(a1/a2)-1+1. The cell containing the formula was formatted to percentage. I was wondering why use =sum()-1+1 when +a1/a2 would render the same result (provided the cell is formatted to percentage)? Thank you |
using =sum() to get a percentage
the +1 and -1 cancel each other out... so... no reason... -- Bearacade ------------------------------------------------------------------------ Bearacade's Profile: http://www.excelforum.com/member.php...o&userid=35016 View this thread: http://www.excelforum.com/showthread...hreadid=553690 |
using =sum() to get a percentage
I guess whoever created the formula was just throwing things out there to see
what sticks. Sum isn't needed and -1 +1 would cancel out. I would probably change it to something like =if(a2 = 0, 0, a1/a2) -- Kevin Vaughn " wrote: I recently received a spreadsheet that contained =sum(a1/a2)-1+1. The cell containing the formula was formatted to percentage. I was wondering why use =sum()-1+1 when +a1/a2 would render the same result (provided the cell is formatted to percentage)? Thank you |
using =sum() to get a percentage
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using =sum() to get a percentage
No reason, total overkill.
-- HTH Bob Phillips (replace xxxx in the email address with gmail if mailing direct) wrote in message ups.com... I recently received a spreadsheet that contained =sum(a1/a2)-1+1. The cell containing the formula was formatted to percentage. I was wondering why use =sum()-1+1 when +a1/a2 would render the same result (provided the cell is formatted to percentage)? Thank you |
using =sum() to get a percentage
Tad harsh don't you think?
-- HTH Bob Phillips (replace xxxx in the email address with gmail if mailing direct) "Ardus Petus" wrote in message ... The author of the workbook you received is a pervert. :-) -- AP a écrit dans le message de news: ... I recently received a spreadsheet that contained =sum(a1/a2)-1+1. The cell containing the formula was formatted to percentage. I was wondering why use =sum()-1+1 when +a1/a2 would render the same result (provided the cell is formatted to percentage)? Thank you |
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