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Count the number of unique records
I have this table of data:
refid Date 95528 10/22/2004 95528 10/22/2004 95312 10/22/2004 95312 10/22/2004 95261 10/22/2004 95261 10/22/2004 95051 10/23/2004 95051 10/23/2004 95051 10/23/2004 94999 10/23/2004 94999 10/23/2004 94806 10/24/2004 94806 10/24/2004 94737 10/24/2004 94737 10/24/2004 94678 10/24/2004 I need to do a count only counts a REFID once and only between certian dates. So, sort of count the number of REFID's that fall on 10/23/2004. Make sence? Also, it needs to be done in one formula. Obviously this requires an array formula. I have a formula that counts the number of entires between certian dates, but I can't figure out how to count a REFID only once. Cheers! |
Count the number of unique records
If you want to count only once the unique, this comes close but I get a 0.
Maybe someone could help this poor formula out to give 1 as an answer? Array entered: =SUM(IF(FREQUENCY(IF((A2:A17=95528)*(B2:B17="10/22/2004"),MATCH(A2:A17,A2:A17,0),""),IF((A2:A17=95528 )*(B2:B17="10/22/2004"),MATCH(A2:A17,A2:A17,0),""))0,1)) " wrote: I have this table of data: refid Date 95528 10/22/2004 95528 10/22/2004 95312 10/22/2004 95312 10/22/2004 95261 10/22/2004 95261 10/22/2004 95051 10/23/2004 95051 10/23/2004 95051 10/23/2004 94999 10/23/2004 94999 10/23/2004 94806 10/24/2004 94806 10/24/2004 94737 10/24/2004 94737 10/24/2004 94678 10/24/2004 I need to do a count only counts a REFID once and only between certian dates. So, sort of count the number of REFID's that fall on 10/23/2004. Make sence? Also, it needs to be done in one formula. Obviously this requires an array formula. I have a formula that counts the number of entires between certian dates, but I can't figure out how to count a REFID only once. Cheers! |
Count the number of unique records
Array entered... this gives 1 as an answer (is this helpful ?)
=SUM(IF(FREQUENCY(IF((A2:A17=D1)*(B2:B17=C1),MATCH (B2:B17,B2:B17,0),""),IF((A2:A17=D1)*(B2:B17=C1),M ATCH(B2:B17,B2:B17,0),""))0,1)) Where C1 is your date and D1 is the redfid number. "GerryK" wrote: If you want to count only once the unique, this comes close but I get a 0. Maybe someone could help this poor formula out to give 1 as an answer? Array entered: =SUM(IF(FREQUENCY(IF((A2:A17=95528)*(B2:B17="10/22/2004"),MATCH(A2:A17,A2:A17,0),""),IF((A2:A17=95528 )*(B2:B17="10/22/2004"),MATCH(A2:A17,A2:A17,0),""))0,1)) " wrote: I have this table of data: refid Date 95528 10/22/2004 95528 10/22/2004 95312 10/22/2004 95312 10/22/2004 95261 10/22/2004 95261 10/22/2004 95051 10/23/2004 95051 10/23/2004 95051 10/23/2004 94999 10/23/2004 94999 10/23/2004 94806 10/24/2004 94806 10/24/2004 94737 10/24/2004 94737 10/24/2004 94678 10/24/2004 I need to do a count only counts a REFID once and only between certian dates. So, sort of count the number of REFID's that fall on 10/23/2004. Make sence? Also, it needs to be done in one formula. Obviously this requires an array formula. I have a formula that counts the number of entires between certian dates, but I can't figure out how to count a REFID only once. Cheers! |
Count the number of unique records
Looks like its gettting close. I'll have to work on that formula a bit.
Thanks for the reccomendation. |
Count the number of unique records
This one is VERY cpu intensive.
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Count the number of unique records
Wait, I lied.
=SUMPRODUCT(--(MONTH($D$3:$D$10000)=$F5),($C$3:$C$10000<"")/COUNTIF($C$3:$C$10000,$C$3:$C$10000&"")) (this is entered as an array formula) Also, where $F5 is the month number in question (IE 12 for December) This works, its just VERY cpu intensive. |
Count the number of unique records
You can probably obtain a better performance score with:
=COUNTDIFF(IF($D$3:$D$10000-DAY($D$3:$D$10000)+1=$F5,$C$3:$C$10000,""),FALSE," ") which must be confirmed with control+shift+enter, not just with enter. Note 1. You need to download and install the morefunc.xll add-in. Note 2. F5 must house the first day date of a month/year of interest. For example: 1-Oct-2004. Take notice of 1 as day number. Note 3. If C:D is sorted in ascending order on column D, we can do even better qua performance. wrote: Wait, I lied. =SUMPRODUCT(--(MONTH($D$3:$D$10000)=$F5),($C$3:$C$10000<"")/COUNTIF($C$3:$C$10000,$C$3:$C$10000&"")) (this is entered as an array formula) Also, where $F5 is the month number in question (IE 12 for December) This works, its just VERY cpu intensive. |
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