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#1
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Column() to return a letter instead of a number?
Can column() return a letter instead of a number? I am planning to use it with INDIRECT? Is that possible? =INDIRECT(row() & column())? -- cKBoy ------------------------------------------------------------------------ cKBoy's Profile: http://www.excelforum.com/member.php...o&userid=31522 View this thread: http://www.excelforum.com/showthread...hreadid=512119 |
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#2
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Column() to return a letter instead of a number?
Hi yes, it's possible, insert this into your formula: CHAR(COLUMN()+64) hth Rob Brockett NZ Always learning & the best way to learn is to experience... -- broro183 ------------------------------------------------------------------------ broro183's Profile: http://www.excelforum.com/member.php...o&userid=30068 View this thread: http://www.excelforum.com/showthread...hreadid=512119 |
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#3
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Column() to return a letter instead of a number?
Awesome! worked like a charm... Thanks! :) -- cKBoy ------------------------------------------------------------------------ cKBoy's Profile: http://www.excelforum.com/member.php...o&userid=31522 View this thread: http://www.excelforum.com/showthread...hreadid=512119 |
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#4
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Column() to return a letter instead of a number?
pleased I could help :-) I hope the issue of columns greater than Z don't cause any problems... Rob Brockett NZ Always learning & the best way to learn is to experience... -- broro183 ------------------------------------------------------------------------ broro183's Profile: http://www.excelforum.com/member.php...o&userid=30068 View this thread: http://www.excelforum.com/showthread...hreadid=512119 |
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#5
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Column() to return a letter instead of a number?
oh, =INDIRECT(CHAR(COLUMN(E5)+64)&ROW()) worked, but what if I wanted to get the cell from a different sheet but the same cell location? ie. =INDIRECT(Sheet1.CHAR(COLUMN(E5)+64)&ROW()) -- but this didn't work, is there something missing from the function? -- cKBoy ------------------------------------------------------------------------ cKBoy's Profile: http://www.excelforum.com/member.php...o&userid=31522 View this thread: http://www.excelforum.com/showthread...hreadid=512119 |
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#6
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Column() to return a letter instead of a number?
try
=INDIRECT("sheet1!"&LEFT(ADDRESS(1,COLUMN(sheet1!E 5),4),IF(COLUMN(sheet1!E5)<27,1,2))&ROW(sheet1!E5) ) ---- Ioannis, Athens "cKBoy" wrote: oh, =INDIRECT(CHAR(COLUMN(E5)+64)&ROW()) worked, but what if I wanted to get the cell from a different sheet but the same cell location? ie. =INDIRECT(Sheet1.CHAR(COLUMN(E5)+64)&ROW()) -- but this didn't work, is there something missing from the function? -- cKBoy ------------------------------------------------------------------------ cKBoy's Profile: http://www.excelforum.com/member.php...o&userid=31522 View this thread: http://www.excelforum.com/showthread...hreadid=512119 |
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#7
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Column() to return a letter instead of a number?
=INDIRECT(Sheet1.CHAR(COLUMN(E5)+64)&ROW())
Try putting it as: =INDIRECT("'Sheet1'!"&CHAR(COLUMN(E5)+64)&ROW()) -- Max Singapore http://savefile.com/projects/236895 xdemechanik --- |
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#8
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Column() to return a letter instead of a number?
Hi broro183,
I was working on this sort of problem only last night using the same idea of CHAR(COLUMN() + 64). I fiddled around for ages to overcome the problem of going beyond column Z and came up with =IF(INT((COLUMN()-1)/26)<1,"",CHAR(64 + INT((COLUMN()-1)/26))) & CHAR(64 + MOD(COLUMN() + 25,26) +1) It works but is far too cryptic to actually remember. I later thought that the ADDRESS function might offer a better solution and came up with =LEFT(ADDRESS(ROW(),COLUMN(),4),LEN(ADDRESS(ROW(), COLUMN(),4)) -LEN(ROW())) which just extracts the column address characters from the string returned by the ADDRESS function, which is more straight forward than the previous formula. Just thought you might be interested:-) Ken Johnson |
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#9
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Column() to return a letter instead of a number?
Hi Ken, Thanks, I really like seeing the other options which are available "outside the square of" my knowledge :-) You're right, it is cryptic & although I overlooked the use of "Address", I'd never have even thought of the use of "Int". I think Ioannis has beaten us both though - IMHO, the use of "If" in LEFT(ADDRESS(1,COLUMN(),4),IF(COLUMN()<27,1,2) is the tidiest approach of all. Cheers Rob Brockett NZ always learning & the best way to learn is to experience... Ken Johnson Wrote: Hi broro183, I was working on this sort of problem only last night using the same idea of CHAR(COLUMN() + 64). I fiddled around for ages to overcome the problem of going beyond column Z and came up with =IF(INT((COLUMN()-1)/26)<1,"",CHAR(64 + INT((COLUMN()-1)/26))) & CHAR(64 + MOD(COLUMN() + 25,26) +1) It works but is far too cryptic to actually remember. I later thought that the ADDRESS function might offer a better solution and came up with =LEFT(ADDRESS(ROW(),COLUMN(),4),LEN(ADDRESS(ROW(), COLUMN(),4)) -LEN(ROW())) which just extracts the column address characters from the string returned by the ADDRESS function, which is more straight forward than the previous formula. Just thought you might be interested:-) Ken Johnson -- broro183 ------------------------------------------------------------------------ broro183's Profile: http://www.excelforum.com/member.php...o&userid=30068 View this thread: http://www.excelforum.com/showthread...hreadid=512119 |
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#10
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Column() to return a letter instead of a number?
It works only until column Z, if cKBoy needs two-letter column identifiers
(AA, AB, ...) as well, he should use =LEFT(ADDRESS(1,COLUMN(),4,1),IF(CODE(MID(ADDRESS( 1,COLUMN(),4,1),2,1))57,2,1)) Regards, Stefi broro183 ezt *rta: Hi yes, it's possible, insert this into your formula: CHAR(COLUMN()+64) hth Rob Brockett NZ Always learning & the best way to learn is to experience... -- broro183 ------------------------------------------------------------------------ broro183's Profile: http://www.excelforum.com/member.php...o&userid=30068 View this thread: http://www.excelforum.com/showthread...hreadid=512119 |
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#11
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Column() to return a letter instead of a number?
if column =AA?
so better =LEFT(ADDRESS(1,COLUMN(),4),IF(COLUMN()<27,1,2)) ------- Ioannis, Athens "cKBoy" wrote: Can column() return a letter instead of a number? I am planning to use it with INDIRECT? Is that possible? =INDIRECT(row() & column())? -- cKBoy ------------------------------------------------------------------------ cKBoy's Profile: http://www.excelforum.com/member.php...o&userid=31522 View this thread: http://www.excelforum.com/showthread...hreadid=512119 |
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#12
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Column() to return a letter instead of a number?
It's interesting why obvious solutions don't come up sometimes!
Stefi ΓΙΑΝΝΗΣ Χ.Β. ezt *rta: if column =AA? so better =LEFT(ADDRESS(1,COLUMN(),4),IF(COLUMN()<27,1,2)) ------- Ioannis, Athens "cKBoy" wrote: Can column() return a letter instead of a number? I am planning to use it with INDIRECT? Is that possible? =INDIRECT(row() & column())? -- cKBoy ------------------------------------------------------------------------ cKBoy's Profile: http://www.excelforum.com/member.php...o&userid=31522 View this thread: http://www.excelforum.com/showthread...hreadid=512119 |
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#13
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Column() to return a letter instead of a number?
Hi, CkBoy, to answer your question about the indirect function, I've put together your attempt with Ioannis', try: =INDIRECT("'sheet 2'!"&LEFT(ADDRESS(1,COLUMN(),4),IF(COLUMN()<27,1,2 )&ROW())) NB: The single apostrphes on each side of the sheet name mean that the formula will work if the sheet name has spaces in it. The "sheet 2" can be replaced with the appropriate sheet name or if you have a list of sheet names (eg the first one is in cell A2 of the active sheet) try: =INDIRECT("'"&A2&"'!"&LEFT(ADDRESS(1,COLUMN(),4),I F(COLUMN()<27,1,2)&ROW())) btw, Stefi/Ioannis, yes, you're right it is interesting why the obvious doesn't come up straight away - Thanks for showing me something new :-) hth Rob Brockett NZ always learning & the best way to learn is to experience... -- broro183 ------------------------------------------------------------------------ broro183's Profile: http://www.excelforum.com/member.php...o&userid=30068 View this thread: http://www.excelforum.com/showthread...hreadid=512119 |
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