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calculating commissions for a range of values
Hello, I have read the threads about similar problems on this site, but nothing seems to work for me so perhaps I am doing something wrong. I need to calculate commission varying by range: .5% of sales up to 100 .75% of sales from 100 to 150 1% of sales above 150 I have tried using the IF function but can't figure out if there is a way to signify "if less than x AND greater than y, then z". -- abryan ------------------------------------------------------------------------ abryan's Profile: http://www.excelforum.com/member.php...o&userid=29118 View this thread: http://www.excelforum.com/showthread...hreadid=488361 |
calculating commissions for a range of values
See
http://www.mcgimpsey.com/excel/variablerate.html In article , abryan wrote: Hello, I have read the threads about similar problems on this site, but nothing seems to work for me so perhaps I am doing something wrong. I need to calculate commission varying by range: .5% of sales up to 100 .75% of sales from 100 to 150 1% of sales above 150 I have tried using the IF function but can't figure out if there is a way to signify "if less than x AND greater than y, then z". |
calculating commissions for a range of values
You could reformulate the issue as:
..5% of sales PLUS .25% of sales over 100 PLUS .25% of sales above 150 Which translates into =a1*0.5% + max(0,a1-100)*.25% + max(0,a1-150)*.25%. --Bruce "abryan" wrote: Hello, I have read the threads about similar problems on this site, but nothing seems to work for me so perhaps I am doing something wrong. I need to calculate commission varying by range: .5% of sales up to 100 .75% of sales from 100 to 150 1% of sales above 150 I have tried using the IF function but can't figure out if there is a way to signify "if less than x AND greater than y, then z". -- abryan ------------------------------------------------------------------------ abryan's Profile: http://www.excelforum.com/member.php...o&userid=29118 View this thread: http://www.excelforum.com/showthread...hreadid=488361 |
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