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Simplify syntax of a Sum(IF... Array
{=SUM(IF((LEFT(TEXT($A6,"mm"),2))=((LEFT(TEXT('Wee kly Total - 2005'!$B$4:$B$123,"mm"),2))),'Weekly Total - 2005'!E$4:E$123,"-"))} Can this be simplified .... -- JustMe602 ------------------------------------------------------------------------ JustMe602's Profile: http://www.excelforum.com/member.php...o&userid=27854 View this thread: http://www.excelforum.com/showthread...hreadid=474003 |
I've omitted the worksheet name, but have you tried something like this?
=SUMPRODUCT((MONTH($B$4:$B$123)=MONTH($A6))*E$4:$E $123) Also, a Pivot Table may help. You can group dates by month, month and year, etc. On Thu, 6 Oct 2005 20:30:09 -0500, JustMe602 wrote: {=SUM(IF((LEFT(TEXT($A6,"mm"),2))=((LEFT(TEXT('We ekly Total - 2005'!$B$4:$B$123,"mm"),2))),'Weekly Total - 2005'!E$4:E$123,"-"))} Can this be simplified .... |
One way, still keeping it as an *array* formula:
=SUM(IF(TEXT($A6,"mm")=TEXT('Weekly Total - 2005'!$B$4:$B$123,"mm"),'Weekly Total - 2005'!E$4:E$123,"-")) If you could live with a zero instead of the dash ( - ), when no data meets the criteria, you could try this *regular*, *non-array* formula: =SUMPRODUCT((TEXT($A6,"mm")=TEXT('Weekly Total - 2005'!$B$4:$B$123,"mm"))*('Weekly Total - 2005'!E$4:E$123)) "JustMe602" wrote in message ... {=SUM(IF((LEFT(TEXT($A6,"mm"),2))=((LEFT(TEXT('Wee kly Total - 2005'!$B$4:$B$123,"mm"),2))),'Weekly Total - 2005'!E$4:E$123,"-"))} Can this be simplified .... -- JustMe602 ------------------------------------------------------------------------ JustMe602's Profile: http://www.excelforum.com/member.php...o&userid=27854 View this thread: http://www.excelforum.com/showthread...hreadid=474003 |
Actually, all the formulas return zero in the absence of a match, so, use
the Sumproduct as a more efficient approach. -- Regards, RD --------------------------------------------------------------------------- Please keep all correspondence within the NewsGroup, so all may benefit ! --------------------------------------------------------------------------- "RagDyer" wrote in message ... One way, still keeping it as an *array* formula: =SUM(IF(TEXT($A6,"mm")=TEXT('Weekly Total - 2005'!$B$4:$B$123,"mm"),'Weekly Total - 2005'!E$4:E$123,"-")) If you could live with a zero instead of the dash ( - ), when no data meets the criteria, you could try this *regular*, *non-array* formula: =SUMPRODUCT((TEXT($A6,"mm")=TEXT('Weekly Total - 2005'!$B$4:$B$123,"mm"))*('Weekly Total - 2005'!E$4:E$123)) "JustMe602" wrote in message ... {=SUM(IF((LEFT(TEXT($A6,"mm"),2))=((LEFT(TEXT('Wee kly Total - 2005'!$B$4:$B$123,"mm"),2))),'Weekly Total - 2005'!E$4:E$123,"-"))} Can this be simplified .... -- JustMe602 ------------------------------------------------------------------------ JustMe602's Profile: http://www.excelforum.com/member.php...o&userid=27854 View this thread: http://www.excelforum.com/showthread...hreadid=474003 |
If you could live with a zero instead of the dash ( - ), when no data meets
the criteria The use of the dash is superfluous. Where the logical test is FALSE, the dashes are just TEXT elements in the summed array: =SUM({100;22;"-";50;"-"}) Since SUM ignores text, no harm done and if all elements of the array were text, SUM = 0. Biff "RagDyer" wrote in message ... One way, still keeping it as an *array* formula: =SUM(IF(TEXT($A6,"mm")=TEXT('Weekly Total - 2005'!$B$4:$B$123,"mm"),'Weekly Total - 2005'!E$4:E$123,"-")) If you could live with a zero instead of the dash ( - ), when no data meets the criteria, you could try this *regular*, *non-array* formula: =SUMPRODUCT((TEXT($A6,"mm")=TEXT('Weekly Total - 2005'!$B$4:$B$123,"mm"))*('Weekly Total - 2005'!E$4:E$123)) "JustMe602" wrote in message ... {=SUM(IF((LEFT(TEXT($A6,"mm"),2))=((LEFT(TEXT('Wee kly Total - 2005'!$B$4:$B$123,"mm"),2))),'Weekly Total - 2005'!E$4:E$123,"-"))} Can this be simplified .... -- JustMe602 ------------------------------------------------------------------------ JustMe602's Profile: http://www.excelforum.com/member.php...o&userid=27854 View this thread: http://www.excelforum.com/showthread...hreadid=474003 |
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