I demonstrate that the Normal distribution is a good approximation of the
binomial in Excel but I found there was a diference in entering the formula


f(x)=1/(stdev*sqrt(2*PI()))*exp(-(x-mean)^2/(2*stdev^2))
and
NORMDIST(x, mean, stdev, false)

For example, for the binomial n=25, p=0.25
binomdist(6,25,0.25,false)=0.182820
normdist(6, np, sqrt(npq),false)=0.183039
f(6)=0.184116

Could someone explain where the difference between NORMDIST and f(x) comes
from?

Thanks!