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Hi
I'm trying to locate a formula that can calculate what I have to charge based on the below tier structu Items Cost 1-1250 £1.50 1251-1500 £1.25 1501-1750 £1.00 1750+ £0.75 If a figure of 1550 was placed into a cell then the price I have to charge based on the above tiered structure should be £2237.50 i.e. First 1250 items equals £1875.00 Next 250 items equals 312.50 Next 50 items equals £50.00 does such formula exist? Thanks, in advance, for any assistance that can be provided. |
#2
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Hi,
Am Mon, 9 Sep 2013 05:59:05 -0700 (PDT) schrieb : Items Cost 1-1250 £1.50 1251-1500 £1.25 1501-1750 £1.00 1750+ £0.75 write in A2:B5: 1.5 1250 1.25 1500 1 1750 0.75 10000 and in C2 your items e.g. 1550 Then: =SUMPRODUCT(((B2:B5)-(B1:B4))*(C$2B1:B4),A2:A5)-(MIN(IF(B2:B5=C2,B2:B5))-C2)*INDEX(A2:A5,MATCH(MIN(IF(B2:B5=C2,B2:B5)),B2: B5,0)) and enter the array formula with CTRL+Shift+Enter Regards Claus B. -- Win XP PRof SP2 / Vista Ultimate SP2 Office 2003 SP2 /2007 Ultimate SP2 |
#3
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On Monday, 9 September 2013 13:59:05 UTC+1, wrote:
Hi I'm trying to locate a formula that can calculate what I have to charge based on the below tier structu Items Cost 1-1250 £1.50 1251-1500 £1.25 1501-1750 £1.00 1750+ £0.75 If a figure of 1550 was placed into a cell then the price I have to charge based on the above tiered structure should be £2237.50 i.e. First 1250 items equals £1875.00 Next 250 items equals 312.50 Next 50 items equals £50.00 does such formula exist? Thanks, in advance, for any assistance that can be provided. Fantastic Claus - thank you so much :-) |
#4
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#5
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On Monday, 9 September 2013 13:59:05 UTC+1, wrote:
Hi I'm trying to locate a formula that can calculate what I have to charge based on the below tier structu Items Cost 1-1250 £1.50 1251-1500 £1.25 1501-1750 £1.00 1750+ £0.75 If a figure of 1550 was placed into a cell then the price I have to charge based on the above tiered structure should be £2237.50 i.e. First 1250 items equals £1875.00 Next 250 items equals 312.50 Next 50 items equals £50.00 does such formula exist? Thanks, in advance, for any assistance that can be provided. Thanks Ron - both work perfectly :-) |
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