Counting rows containing data (both numbers and text)
I've got numerous spreadsheets containing approx. 30K rows of data, with
blank rows used to seperate groups of data. I need to count how many rows contain data, without counting the blank rows. I think it's probably a COUNT IF function, but I'm not sure. I'm not a very advanced user, so please be very specific in your reply. Thank You |
I would say it shoud be COUNTA rather than COUNTIF. Try something like:
=COUNTA(A:A) to count non-empty cells in the column [A] Regards, KL "mconnolly" wrote in message ... I've got numerous spreadsheets containing approx. 30K rows of data, with blank rows used to seperate groups of data. I need to count how many rows contain data, without counting the blank rows. I think it's probably a COUNT IF function, but I'm not sure. I'm not a very advanced user, so please be very specific in your reply. Thank You |
One way:
If every filled row has a value in column A: =COUNTA(A:A) In article , mconnolly wrote: I've got numerous spreadsheets containing approx. 30K rows of data, with blank rows used to seperate groups of data. I need to count how many rows contain data, without counting the blank rows. I think it's probably a COUNT IF function, but I'm not sure. I'm not a very advanced user, so please be very specific in your reply. Thank You |
Try:
=counta(a1:a100) "mconnolly" wrote: I've got numerous spreadsheets containing approx. 30K rows of data, with blank rows used to seperate groups of data. I need to count how many rows contain data, without counting the blank rows. I think it's probably a COUNT IF function, but I'm not sure. I'm not a very advanced user, so please be very specific in your reply. Thank You |
Use the COUNTA() function, i.e.,
=COUNTA(A1:A30000) "mconnolly" wrote: I've got numerous spreadsheets containing approx. 30K rows of data, with blank rows used to seperate groups of data. I need to count how many rows contain data, without counting the blank rows. I think it's probably a COUNT IF function, but I'm not sure. I'm not a very advanced user, so please be very specific in your reply. Thank You |
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